URL: LeetCode Problem
Problem Description
Given the head of a singly linked list, reverse the list, and return the reversed list.
Examples:
- Example 1:
Input: head = [1,2,3,4,5]
Output: [5,4,3,2,1]
Constraints:
- The number of nodes in the list is the range [0, 5000].
- 5000 <= Node.val <= 5000
Answer
Complexity
Time complexity: O(n)
Space complexity: O(1)
Code
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def reverseList(self, head: Optional[ListNode]) -> Optional[ListNode]:
prev = None
while head:
next_node = head.next
head.next = prev
prev = head
head = next_node
return prev