URL: LeetCode Problem
Problem Description
Write an algorithm to determine if a number n is happy.
A happy number is a number defined by the following process:
Starting with any positive integer, replace the number by the sum of the squares of its digits. Repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy. Return true if n is a happy number, and false if not.
Examples:
Example 1:
Input: n = 19 Output: true Explanation: 12 + 92 = 82 82 + 22 = 68 62 + 82 = 100 12 + 02 + 02 = 1
Constraints:
- 1 <= n <= 231 - 1
Python3 Solution
Apply the two pointers method and if slow and fast meet, it means the number is not happy.
class Solution:
def numSquareSum(self, n):
rtn = 0
while n > 0:
rtn += (n%10)*(n%10)
n = n//10
return rtn
def isHappy(self, n):
fast = slow = n
while n > 0:
slow = self.numSquareSum(slow)
fast = self.numSquareSum(self.numSquareSum(fast))
if slow is fast:
return slow == 1