URL: LeetCode Problem
Problem Description
Given the root of a binary tree, return the average value of the nodes on each level in the form of an array. Answers within 10-5 of the actual answer will be accepted.
Examples:
- Example 1:
Input: root = [3,9,20,null,null,15,7] Output: [3.00000,14.50000,11.00000] Explanation: The average value of nodes on level 0 is 3, on level 1 is 14.5, and on level 2 is 11. Hence return [3, 14.5, 11].
Constraints:
The number of nodes in the tree is in the range [1, 104]. -231 <= Node.val <= 231 - 1
Python3 Solution
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def averageOfLevels(self, root: Optional[TreeNode]) -> List[float]:
ans = []
# nodes store
q = deque()
q.append(root)
while q:
# list of node values on same levels
level = []
for _ in range(len(q)):
popping = q.popleft()
if popping:
level.append(popping.val)
q.append(popping.left)
q.append(popping.right)
if level:
ans.append(level)
return [sum(nums)/len(nums) for nums in ans]